Second Highest Marks In Sql Method 2 Syntax SELECT column name FROM table name e WHERE 2 SELECT COUNT DISTINCT column name FROM table name p WHERE e column name p column name This is a nested sub query which is a generic SQL query to print the Nth largest value in column
Let s discuss 11 different ways to select second highest value in MS SQL table And as a bonus 6 different ways to select the Nth highest value I will be using a table called WorkOrder with three columns in it WorkOrderID ProductID OrderQty Here is a quick look to our table WorkOrderID ProductID OrderQty Below is a simple query to find the employee whose salary is the highest select from employee where salary select Max salary from employee Note Depending on the default settings and MySQL version we may receive ERROR 1140 when running this query on the MySQL database The solution can be found in the article s final section
Second Highest Marks In Sql
Second Highest Marks In Sql
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Multiple Ways To Get Second And Nth Highest Salary In SQL
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How To Find Second Highest Salary In SQL Step by Step
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Solution This SQL tutorial will show how the SQL Server window function DENSE RANK can be leveraged to get the nth highest record from a table The SQL Server DENSE RANK function attaches a rank with each row inside the result set partition The DENSE RANK method in contrast to the RANK method returns a series of rank values For example the highest and lowest marks in the complete result set are 90 and 50 respectively In the result set the highest mark gets RANK 1 and the lowest mark gets RANK 9 If two students get the same marks in our example ROW numbers 4 and 5 their ranks are also the same
By using order by command we can display the records in the order by marks By adding the command DESC we can get the records starting from highest to lowest records So we will get first record of the highest mark and then the second highest mark We know we can restrict the number of display by using limit command so we will use this limit 2 Answers You can use window functions for this select col a col b from select col a col b dense rank over partition by col a order by col b desc as rnk from the table t where rnk 2 Accepting this one because it s much faster and shorter Assuming distinct values per group
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Output Now to find the second highest salary we nest the above query into another query as written below SELECT MAX SALARY FROM Employee WHERE SALARY SELECT MAX SALARY FROM Employee This query will give you the desired output i e 12000 which is the second highest salary The SQL MIN and MAX Functions The MIN function returns the smallest value of the selected column The MAX function returns the largest value of the selected column
And this query should do your job First we are sorting the table in descending way so the person with the highest salary is at the top and the second highest is at the second position Now limit a b means skip the starting a elements and then print the next b elements So you should use limit 1 1 in this case Hope this helps As clearly shown in the output the second and third rows share the same rank because they have the same value The fourth row gets the rank 4 because the RANK function skips the rank 3 Note that if you want to have consecutive ranks you can use the DENSE RANK function SQL RANK function examples We will use the employees and departments table from the sample database for the
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Second Highest Marks In Sql - IN SELECT MAX emp salary FROM employee The above query will give you the second highest salary from the employee table Basically doing a sub query to find out the actual MAX value then again checking with NOT IN function to eliminate the actual MAX value and to show the second highest value Post Views 6 719